// Time Complexity: O(n²) (due to substring creation and window reset) } else if (right == s.length() - 1 && !(map.containsKey(s.substring(left, right + 1)))) { map ...
// For a balanced substring with one char, any length works (all chars are equal) maxlen = Math.max(maxlen, getLength(s, 'a')); // Consider 'b' and 'c' maxlen = Math ...
Most Java programmers have used the java.util.StringTokenizer class at some time or another. It is a handy class that basically tokenizes (breaks) the input string based on a separator, and supplies ...
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