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You can design a small Python game with AI using the pygame library. Below is an example of a simple Tic-Tac-Toe game where the computer uses the Minimax algorithm to play optimally, making it unbeatable.
Steps to Build
1. Install Pygame
pip install pygameCopied!✕Copy2. Create the Game Logic with AI
import mathimport pygame# Initialize Pygamepygame.init()WIDTH, HEIGHT = 300, 300LINE_WIDTH = 5WHITE, BLACK = (255, 255, 255), (0, 0, 0)screen = pygame.display.set_mode((WIDTH, HEIGHT))pygame.display.set_caption("Tic-Tac-Toe AI")board = [" " for _ in range(9)]current_player = "X"def draw_board():screen.fill(WHITE)for i in range(1, 3):pygame.draw.line(screen, BLACK, (0, i*100), (300, i*100), LINE_WIDTH)pygame.draw.line(screen, BLACK, (i*100, 0), (i*100, 300), LINE_WIDTH)for idx, mark in enumerate(board):x = (idx % 3) * 100 + 40y = (idx // 3) * 100 + 40if mark != " ":font = pygame.font.Font(None, 60)text = font.render(mark, True, BLACK)screen.blit(text, (x, y))pygame.display.flip()def check_winner(b):wins = [(0,1,2),(3,4,5),(6,7,8),(0,3,6),(1,4,7),(2,5,8),(0,4,8),(2,4,6)]for a,b_,c in wins:if board[a] == board[b_] == board[c] != " ":return board[a]return Nonedef minimax(b, depth, is_max):winner = check_winner(b)if winner == "O": return 1if winner == "X": return -1if " " not in b: return 0if is_max:best_score = -math.inffor i in range(9):if b[i] == " ":b[i] = "O"score = minimax(b, depth+1, False)b[i] = " "best_score = max(score,best_score)return best_scoreelse:best_score = math.inffor i in range(9):if b[i] == " ":b[i] = "X"score = minimax(b, depth+1, True)b[i] = " "best_score = min(score,best_score)return best_scoredef ai_move():best_score = -math.infmove = Nonefor i in range(9):if board[i] == " ":board[i] = "O"score = minimax(board,0,False)board[i] = " "if score > best_score:best_score = scoremove = iboard[move] = "O"# Game Looprunning = Truewhile running:draw_board()for event in pygame.event.get():if event.type == pygame.QUIT: running=Falseelif event.type == pygame.MOUSEBUTTONDOWN and current_player=="X":x,y=pygame.mouse.get_pos()idx=(y//100)*3+(x//100)if board[idx]==" ":board[idx]="X"if not check_winner(board) and " " in board:ai_move()draw_board()pygame.quit()Copied!✕Copy Tutorial and Demo: How to Build a Voice AI Video Game in Python
In this article, we are going to transform an ordinary platformer game into one that can be controlled by your voice using Deepgram’s API.
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